7th term of sequence roo2,root10,5root2,.....
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5root1250.
The quantity inside the root is getting 5 times the previous one. First term is root2 the second is root10 then third is 5root2 which is nothing but root50......then comes root250 then root1250 then root6250 then root31250
root 31250 is the 7th term which can also be written as root(25×1250)=5root1250
The quantity inside the root is getting 5 times the previous one. First term is root2 the second is root10 then third is 5root2 which is nothing but root50......then comes root250 then root1250 then root6250 then root31250
root 31250 is the 7th term which can also be written as root(25×1250)=5root1250
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the answer is 125√2 as the square of each term is 5 times the previous one
sriram77:
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