Question

7th term of th sequence root2 ,root 10, 5 root 2 , is?

Answer 1

Step-by-step explanation:

hope it helps

mark as brainliest

Answer 2

The 7th term of G.P is $a_7=125\sqrt2$

Step-by-step explanation:

Given : Sequence $\sqrt{2},\sqrt{10},5\sqrt{2},..$

To find : 7th term of the sequence ?

Solution :

Sequence $\sqrt{2},\sqrt{10},5\sqrt{2},..$ form a geometric progression.

Where, the first term is $a=\sqrt{2}$

and common ratio is $r=\frac{\sqrt{10}}{\sqrt2}=\sqrt5$

The 7th term of G.P. is $a_7=ar^6$

Substitute the value,

$a_7=(\sqrt2)(\sqrt5)^6$

$a_7=(\sqrt2)(5)^{\frac{6}{2}}$

$a_7=(\sqrt2)(5)^{3}$

$a_7=125\sqrt2$

Therefore, the 7th term of G.P is $a_7=125\sqrt2$

#Learn more

In a G.p first term is 4 and third term is 144 find the G.p and the sum of first four term?

brainly.in/question/12096620