⅓(7x-1)=¼ please solve it
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(1/3)×(7×x-1) = 1/4 // - 1/4
(1/3)×(7×x-1)-(1/4) = 0
(1/3)×(7×x-1)-1/4 = 0
1/3×(7×x-1)-1/4 = 0
(1/3×4×(7×x-1))/4-1/4 = 0
1/3×4×(7×x-1)-1 = 0
28/3×x-7/3 = 0
(28/3×x-7/3)/4 = 0
(28/3× x-7/3)/4 = 0 // ×4
28/3×x-7/3 = 0
28/3×x-7/3 = 0 // + 7/3
28/3×x = 7/3 // : 28/3
x = 7/3/28/3
x = 1/4
x = 1/45
hope it helps......
pls mark as brainliest,if the answer is correct
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