Math, asked by itzjanvi90, 10 months ago

7x-15y-2=0 x+2y-3=0 ​

Answers

Answered by aniketp20
2

Answer:

7x - 15y = 2 ....eq 1

x + 2y = 3 .....eq2

Multiply eq 2 by 7 and subtract them

-15y - 14y = 2-21

-29y = -19

y = 19/29

Putting value of y in eq 2

x + 2*19/29 = 3

x = 3- 38/29

x= 87/29-38/29

x = 49/29

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Answered by madhulika7
1

Answer:

7x - 15y = 2 \\ \: \implies7x =  2 + 15y  \\ \implies \: x =  \frac{2 + 15y}{7} \:  \:  \:  \:  \: \rightarrow(i) \\  \\ x + 2y = 3 \\  \implies\frac{2 + 15y}{7}  + 2y = 3 \: (putting \: x =  \frac{2 + 15y}{7} ) \\ \implies \frac{2 + 15y + 14y}{7}  = 3 \\ \implies15y + 14y = 3 \times 7 - 2 \\ \implies29y = 21 - 2 \\ \implies \: y =  \frac{19}{29}   \\ \\  \\  \:  \:  substituting \: the \: value \: of \: y \: in \: equation \: (i) \\ 7x - 15 \times  \frac{19}{29}  = 2 \\ \implies7x - \frac{285}{29}  = 2 \\ \implies7x = 2 +  \frac{285}{29}  \\ \implies7x =  \frac{58 + 285}{29}  \\   \\ \:  \implies7x =  \frac{343}{29 }  \\ \\  \implies \: x =  \frac{343}{203} \\  \\  \implies \: x =  \frac{49}{29}  \\  \\ \therefore \: x =  \frac{49}{29}  \\  \\ y =  \frac{19}{29}

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