Question

7x-17/[x^2-3x +4] >= 1​

Answer 1

Answer:

Simplifying

x2 + 7x + -17 = 3x + 4

Reorder the terms:

-17 + 7x + x2 = 3x + 4

Reorder the terms:

-17 + 7x + x2 = 4 + 3x

Solving

-17 + 7x + x2 = 4 + 3x

Solving for variable 'x'.

Reorder the terms:

-17 + -4 + 7x + -3x + x2 = 4 + 3x + -4 + -3x

Combine like terms: -17 + -4 = -21

-21 + 7x + -3x + x2 = 4 + 3x + -4 + -3x

Combine like terms: 7x + -3x = 4x

-21 + 4x + x2 = 4 + 3x + -4 + -3x

Reorder the terms:

-21 + 4x + x2 = 4 + -4 + 3x + -3x

Combine like terms: 4 + -4 = 0

-21 + 4x + x2 = 0 + 3x + -3x

-21 + 4x + x2 = 3x + -3x

Combine like terms: 3x + -3x = 0

-21 + 4x + x2 = 0

Factor a trinomial.

(-7 + -1x)(3 + -1x) = 0

Explanation:

Answer 2

Answer:

solve krne pr,

7x-17>=x2-3x+4

x2-10x-21>=0

(x-7)(x-3)=>0

(-u define, 3]u[7,undefind)