Question

7x^2 - 3x + 2 = 0 by completing square method​

Answer 1

Step-by-step explanation:

$7 {x}^{2} - 3x + 2 = 0 \\ {x}^{2} - \frac{3x}{7} + \frac{2}{7} = 0 \\ {x}^{2} - \frac{3x}{7} = - \frac{2}{7 } \\ {x}^{2} - \frac{3x}{7} + {( \frac{3}{14} )}^{2} = - \frac{2}{7} + {( \frac{3}{14} )}^{2} \\ {(x - \frac{3}{14} )}^{2} = - \frac{2}{7} + \frac{9}{196} \\ {(x - \frac{3}{14} )}^{2} = \frac{ - 56 + 9}{196} \\ x - \frac{3}{14} = - + \frac{ \sqrt{ - 47} }{14} \\ x = \frac{3 + \sqrt{ - 47} }{14} \: \: or \: \: \: x = \frac{3 - \sqrt{ - 47} }{14}$