Question

7x^2-46x-21=0 find roots​

Answer 1

Answer:

7x^2-46x-21=0

Step-by-step explanation:

ax^2+bx+c=0

$b^2-4ac=(-46)^2-4(7)(-21)\\= 2116+588\\=2704\\roots of equation = \frac{-b+1\sqrt{b^2-4ac} }{2a} \\= \frac{-(-46)+-\sqrt{2704} }{2(7)} \\x = \frac{-46+-52 }{14} \\\\x = \frac{-46-52}{14} =\frac{-98}{14} = -7 \\x= \frac{-46+52}{14} = \frac{6}{14} = 3/7$

x = -7 , x = 3/7

roots of 7x^2-46x-21 is -7and 3/7

Answer 2

Answer:

Step-by-step explanation: