Question

7x^2-9x+2=0, solve this problem​

Answer 1

${7x}^{2} - 9x + 2 = 0 \\ {7x}^{2} - 7x - 2x + 2 = 0 \\ 7x(x - 1) - 2(x - 1) = 0 \\ (x - 1)(7x - 2) = 0$

Hence,

${ \huge{Value \: \: of \: \: x \: \: }} \\ \\ { \huge{is \: \: either \: \: 1 \: \: or}} \\ \\ \\ { \huge{ \frac{2}{7} }}$

Answer 2

Step-by-step explanation:

by splitting we get

7x²-7x-2x+2=0

7x(x-1)-2(x-1)=0

(7x-2)(x-1)=0

if the product of two variable is then

one of the term is or both the term is zero so

7x-2=0 or x-1=0

x=2/7 or x=1

thank you

hope it helpful