Math, asked by aryanvashist804, 4 months ago

7x - 21/5 =3/4 - 4/7 solve the equation​

Answers

Answered by Anonymous
3

\huge{\rm{\boxed{\blue{ Solve:- }}}}

7x -  \frac{21}{5}  = \frac{3}{4}  -  \frac{4}{7}

\huge{\rm{\boxed{\pink{ Solution:- }}}}

 = 7x -  \frac{21}{5}  = \frac{3}{4}  -  \frac{4}{7}  \\  =  \frac{5(7x) - 21}{5}  =  \frac{7(3) - 4(4)}{4 \times 7}  \\  =  \frac{35x - 21}{5}  =  \frac{21 - 16}{28}  \\  =  35x - 21  =  \frac{5}{28}  \times 5 \\  = 35x =  \frac{25}{28}   + 21 \\  = 35x =  \frac{25 + 588}{28}  \\  = 35x =  \frac{613}{28}  \\  = x =  \frac{21.8}{35}   \\ = x = 0.62

Hence,

\huge\rm{\boxed{ x = 0.62 }}

#ItzSayan

Answered by Anonymous
13

\Huge\mathcal\blue{\underbrace{\overbrace{\mid{\red{Answer}}\mid}}}

Given-

7x - 21/5 =3/4 - 4/7

It is also a linear equation in one variable

To Find-

the value of x

Solution-

7x - 21/5 =3/4 - 4/7

 =  >  \frac{7x \times 5}{1 \times 5}  -  \frac{21}{5}  =  \frac{3 \times 7}{4 \times 7}  -  \frac{4 \times 4}{7 \times 4}

 \frac{35x - 21}{5}  =  \frac{21 - 16}{28}

 = >  35x - 21 =  \frac{5 \times 5}{28}

 =  > 35x =  \frac{5}{28}  + 21

 =  > 35x =  \frac{5 + 21 \times 28}{28}

 =  > 35x =  \frac{5 + 588}{28}

 =  > 35x =  \frac{593}{28}

 =  > x =  \frac{593}{28 \times 35}

 =  > x =  \frac{593}{980}

 =  > x = 0.605

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