Math, asked by shyamaliaich80, 10 months ago

7x-3y-31=0 9x-5y-41=0 by cross multiplication​

Answers

Answered by nasreendayyed123
5

Step-by-step explanation:

7x-3y-31=0

9x-5y-41=0

mulltiply 7 in eq 2

and multiply 9 in eq 1

by multiplying we get

63x-27 y- 279=0

63x-35y- 287=0

this gives 8y - 8 = 0

so there fore 8y = 8

there fore y is = 1

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