Math, asked by aryaathakur, 11 months ago

7x-3y=31 9x-5y=41 substitution method​

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Answered by ashish125685
9

Answer:

take equation (i)

7x-3y=31

7x=31+3y

x=31+3y/7

now, put the value of x in (2) equation

9x-5y=41

9(31+3y/7) -5y=41

279+27y/7-5y=41

279+27y-35y/7=41

279-8y/7=41

279-8y=41×7

279-8y=287

-8y=287-279

-8y=8

y=-8/8

y=-1

now put the value of y in first equation.

Answered by Rajaak
5

Answer:

Step-by-step explanation:

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7x-3y=31 9x-5y=41 substitution method​

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Answer:

take equation (i)

7x-3y=31

7x=31+3y

x=31+3y/7

now, put the value of x in (2) equation

9x-5y=41

9(31+3y/7) -5y=41

279+27y/7-5y=41

279+27y-35y/7=41

279-8y/7=41

279-8y=41×7

279-8y=287

-8y=287-279

-8y=8

y=-8/8

y=-1

now put the value of y in first equation

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