(7x–4)/(3x+4)= (5x–2)/3x
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Answer:
Applying cross multiplication method.!
(7x-4)×(3x) = (5x-2)×(3x+4)
21x^2-12x = 5x(3x+4) - 2(3x+4)
21x^2-12x = 15x^2+20x - 6x-8
21x^2-15x^2 = 12x+20x-6x - 8
6x^2 = 26x - 8
6x^2 - 26x + 8 = 0
Factorisation method:
(6x^2 - 24x) + (-2x + 8) = 0
6x(x - 4) - 2(x - 4) = 0
(6x-2)(x-4) = 0
2(3x-1)(x-4) = 0
x = 1/3 and 4
Hope it helps.!
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