Question

7x+5/3=48/3- 4x/3. find the value of x​

Answer 1

Answer -

• The value of x is 44/3.

To find -

• The value of x.

Step-by-step explanation -

$\bf\implies\dfrac{7x + 5}{3} = \dfrac{48}{3} - \dfrac{4x}{3}$

$\bf\implies \dfrac{7x + 5}{3} = \dfrac{(48 \times 1) - (4x \times 1)}{3}$

$\bf\implies\dfrac{7x + 5}{3} = \dfrac{48 - 4x}{3}$

$\bf\implies3 \: (48 - 4x) = 3 \: (7x + 5)$

$\bf\implies144 - 12x = 21x + 15$

$\bf\implies144 - 15 = 21x + 12x$

$\bf\implies129 = 33x$

$\bf\implies \cancel{\dfrac{129}{33}} = x$

$\bf\implies \dfrac{43}{11} = x$

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V E R I F I C A T I O N -

• To check our answer, let's substitute the value of x in the equation and see whether LHS = RHS.

LHS :

$\longmapsto\rm \dfrac{7x + 5}{3}$

$\longmapsto\dfrac{7 \times \frac{43}{11} + 5 }{3}$

$\longmapsto\dfrac{ \frac{301}{11} + 5}{3}$

$\longmapsto \dfrac{ \frac{(301 \times 1) + (5 \times 11)}{11} }{3}$

$\longmapsto\dfrac{ \frac{301 + 55}{11} }{3}$

$\longmapsto\dfrac{ \frac{356}{11} }{3}$

$\longmapsto\dfrac{356}{11} \times \dfrac{1}{3}$

$\longmapsto\dfrac{356}{33}$

RHS :

$\longmapsto \rm \dfrac{48}{3} - \dfrac{4x}{3}$

$\longmapsto\dfrac{48}{3} - \dfrac{4 \times \frac{43}{11} }{3}$

$\longmapsto\dfrac{48}{3} - \dfrac{ \frac{172}{11} }{3}$

$\longmapsto\dfrac{48}{3} - \dfrac{172}{11} \times \dfrac{1}{3}$

$\longmapsto\dfrac{48}{3} - \dfrac{172}{33}$

$\longmapsto\dfrac{(48 \times 11) - (172 \times 1)}{33}$

$\longmapsto\dfrac{528 - 172}{33}$

$\longmapsto\dfrac{356}{33}$

LHS = RHS.

Hence verified!!

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Answer 2

Answer:

$\: \: \: \green { \boxed{ \bigstar \: \: \sf \: x = \frac{43}{11} }}$

Step-by-step explanation:

Given,

$\sf\implies\dfrac{7x + 5}{3} = \dfrac{48}{3} - \dfrac{4x}{3} \\ \\ </p><p></p><p>\sf\implies \dfrac{7x + 5}{3} = \dfrac{(48 \times 1) - (4x \times 1)}{3} \\ \\ </p><p></p><p>\sf\implies\dfrac{7x + 5}{3} = \dfrac{48 - 4x}{3} \\ \\ </p><p></p><p>\sf\implies3 \: (48 - 4x) = 3 \: (7x + 5)\\ \\ </p><p></p><p>\sf\implies144 - 12x = 21x + 15\\ \\ </p><p></p><p>\sf\implies144 - 15 = 21x + 12x\\ \\ </p><p></p><p>\sf\implies 33x = 129\\ \\ </p><p></p><p>\sf\implies x = {\frac{ \cancel{129} ^{ \:43}}{ \cancel{33} _{\: 11}}} \: \: \: \pink{\{ \sf\: divided \: by \: 3 \: \}}\\ \\ </p><p></p><p>\sf\implies x =\frac{43}{11} </p><p></p><p> \\ \\ \: \: \: \: \: \green { \boxed{ \therefore \sf \: x = \frac{43}{11} }}$