7x-5y=11,3x+2y=13 by elemination method
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The given equations are as follows :
7x-5y = 11 (i)
3x+2y=13 (ii)
Multiplying equation (i) by 2 and equation (ii) by 5,we have :
14x - 10y = 22 (iii)
15x + 10y = 65 (iv)
Adding equations (iii) and (iv), we have :
29x = 87 (v)
Solving for x, we have :
x = 3 [from equation (v)]
Putting x = 3 in equation (i), we have :
7*3 - 5y = 11
or, 5y = 21-11
or, 5y = 10
or, y = 2.
Hence, for the given system of equations, the values of x and y are 3 and 2 respectively.
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