7x - 5y - 4 = 0 is given. Write another linear equation so that the lines represented by the pairs are:1. intersecting2. coincident3.parallel
Answers
Answered by
7
Hi friend, Here is the required answer:-
7x-5y-4=0
1. 14x-4y+1=0
2.14x-10y-8=0
3. 7x-5y-3=0.
Hope this helps you...
7x-5y-4=0
1. 14x-4y+1=0
2.14x-10y-8=0
3. 7x-5y-3=0.
Hope this helps you...
Anonymous:
Please mark as brainliest!
hey how did u get the ans. did u draw a graph or something
hey check my answer u'll get method
Answered by
8
given
7x -5y -4 = 0 is of form a₁x+b₁y +c₁ = 0
a₁=7 , b₁=-5 c₁=-4
1) for coincident line a₁/a₂ = b₁/b₂ = c₁/c₂
therefore we can take any values for a₂,b₂,c₂ which are in ratio 7 : -5 : -4
eg a₂= 14 b₂ = -10 c₂ = -8
linear eq would be 14x-10y-8=0
2) now parallel a₁/a₂ = b₁/b₂ ≠ c₁/c₂
therefor new eq could be 14x-40y+9=0 as c₂ could be any no except it doesn't form ratio of 7 : -5 : -4
3) for intersecting lines : any line which passes through (2,2) as this point satisfies your eq
eg (y-2)/x-2 = 1 ⇒ y-2 = x-2 ⇒ y=x
hope this helps ...........if any doubt , then ask
7x -5y -4 = 0 is of form a₁x+b₁y +c₁ = 0
a₁=7 , b₁=-5 c₁=-4
1) for coincident line a₁/a₂ = b₁/b₂ = c₁/c₂
therefore we can take any values for a₂,b₂,c₂ which are in ratio 7 : -5 : -4
eg a₂= 14 b₂ = -10 c₂ = -8
linear eq would be 14x-10y-8=0
2) now parallel a₁/a₂ = b₁/b₂ ≠ c₁/c₂
therefor new eq could be 14x-40y+9=0 as c₂ could be any no except it doesn't form ratio of 7 : -5 : -4
3) for intersecting lines : any line which passes through (2,2) as this point satisfies your eq
eg (y-2)/x-2 = 1 ⇒ y-2 = x-2 ⇒ y=x
hope this helps ...........if any doubt , then ask
oh now i got it .actually i was solving this question before reading the topic.now i know the relationship i can solve this question
Similar questions