7x+5y=44, 4х+3y=25
Solve by cross multiplication method
Answers
Answered by
1
Answer:
The given system of equations is 7x+5y−44=0
4x+3y−25=0
Now, writing the coefficients for cross multiplication, we get
−150+150
x
=
−175+90
y
=
18−35
1
. i.e.,
0
x
=
−85
y
=
−17
1
.
Thus, we have x = 0, y = 5. Hence, the solution is (0, 5).
Answered by
1
Answer:
Step-by-step explanation:
7x=44-5y
x=(44-5y)/7
putting the value of in 2nd equation
4(44-5y)/7+3y=25
(176-20y)/7+3y=25
(176-20y+21y)/7=25
176-y=175
-y=175-176
-y=-1
y=1
put the value of y in any eqauation
7x+5y=44
7x+5(1)=44
7x+5=44
7x=44-5
7x=39
x=39/7
x=5.57
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