-7x+8y=2 3x+6y=4 somebody fast
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Step-by-step explanation:
Another solution is to let k=2y and get
x2+3xk+2k2+3x+3k=2
⟺(x2+2xk+k2)+(k2+3xk)+3(x+k)=2⟺(x+k)2+(x+k)(k+3)=2
So now we can let m=x+k and get
m(m+k+3)=2⟹(m,k)∈{(1,−2),(−1,−4),(2,−4),(−2,−2)}
Noting that k=2m−m−3 in our calculations. This gives (after dividing the solutions of k by 2 and putting x=m−k)
(x,y)∈{(3,−1),(3,−2),(6,−2),(0,−1)}
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