Question

(7x-y-6)²+(14x+2y-16)²=0 solve by the method of elimination.​

Answer 1

Answer:

(7x - y -6)^2=0

7x - y - 6=0…eqn1

2′nd term

(14x + 2y -16)^2 =0

7x + y -8 =0… eqn2

solve eqn1 and eqn2

we get x=1 & y=1…

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