(7x2-11x+10)(x3 -x2) find the product.....
Answers
Answer:
Two equations are given
x
3
−7x
2
+14x−8=0 ......... (1) and x
3
−6x
2
+11x−6=0 ........ (2)
We have used synthetic division to solve the given equations.
From part (A), we get the factor of equation (1)
∴ x
3
−7x
2
+14x−8=(x−1)(x
2
−6x+8)
=(x−1)(x
2
−4x−2x+8)
=(x−1)(x(x−4)−2(x−4))
=(x−1)(x−4)(x−2)
∴ x
3
−7x
2
+14x−8=(x−1)(x−2)(x−4) .................. (3)
From part (B), we get the factor of equation (2)
∴ x
3
−6x
2
+11x−6=(x−1)(x
2
−5x+6)
=(x−1)(x
2
−3x−2x+6)
=(x−1)(x(x−3)−2(x−3))
=(x−1)(x−2)(x−3)
∴ x
3
−6x
2
+11x−6=(x−1)(x−2)(x−3) .................. (4)
From equation (3) and (4),
(x−1)(x−2) is the H.C.F(highest common factor) of given equations (1) and (2).
Explanation:
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