Math, asked by likithrmysore, 4 months ago

7x²y*-2/7xz²*-2/5y²z*5x³y²z² =​

Answers

Answered by kavinsiddhu758
3

Answer:

7x^2y\frac{-2}{7}xz^2\frac{-2}{5}y^2z\cdot \:5x^3y^2z^2\\\\= 7x^{2+1+3}y\frac{-2}{7}z^2\frac{-2}{5}y^2z\cdot \:5y^2z^2\\\\= 7x^6y\frac{-2}{7}z^2\frac{-2}{5}y^2z\cdot \:5y^2z^2\\\\= 7x^6y^{1+2+2}\frac{-2}{7}z^2\frac{-2}{5}z\cdot \:5z^2\\\\= 7x^6y^5\frac{-2}{7}z^2\frac{-2}{5}z\cdot \:5z^2\\\\= 7x^6y^5\frac{-2}{7}z^{2+1+2}\frac{-2}{5}\cdot \:5\\\\= 7x^6y^5\frac{-2}{7}z^5\frac{-2}{5}\cdot \:5\\\\= 4x^6y^5z^5

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