Question

7x³ = 45 solve and check​

Answer 1

Step-by-step explanation:

.

$\tt \red{{x}^{3}=\dfrac{45}{7}}$

.

$\tt \pink{x=\sqrt[3]{\dfrac{45}{7}}}$

Use Division Distributive Property: $\sf{(\frac{x}{y})}^{a}=\frac{{x}^{a}}{{y}^{a}}$

$\tt \blue{x=\dfrac{\sqrt[3]{45}}{\sqrt[3]{7}}}$

$\red{ \tt \underline {check : - }}$

Let $\sf x=\frac{\sqrt[3]{45}}{\sqrt[3]{7}}$

$\tt\blue{7{(\dfrac{\sqrt[3]{45}}{\sqrt[3]{7}})}^{3}=45}$

→ Use Division Distributive Property: $\sf{(\dfrac{x}{y})}^{a}=\dfrac{{x}^{a}}{{y}^{a}}$

.

$\tt \red{7\times \dfrac{{(\sqrt[3]{45})}^{3}}{{(\sqrt[3]{7})}^{3}}}$

→ Use this rule: $\sf\sqrt[3]{{x}^{3}}=x$

$\tt\pink{7\times \dfrac{45}{{(\sqrt[3]{7})}^{3}}=45}$

→ Use this rule: $\sf\sqrt[3]{{x}^{3}}=x$

$\tt\orange{7\times \frac{45}{7}=45}$

→ Cancel 7.

45=45

Hope It Help You.

Thanks.