7xsquare - ( 7pi+22 ) x + 22pi = 0
atulakhilesh:
Answer - x=22÷7
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7x^2 - ( 7pi + 22) x +22pi=0
divide by 7 on both sides , we get
x^2 - (pi + 22/7) x +(22*pi)/7=0
we know that pi=22/7
x^2 - 2pi + pi^2=0
(x - pi)^2=0
x= pi=22/7 , x=pi=22/7
divide by 7 on both sides , we get
x^2 - (pi + 22/7) x +(22*pi)/7=0
we know that pi=22/7
x^2 - 2pi + pi^2=0
(x - pi)^2=0
x= pi=22/7 , x=pi=22/7
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