7xy=3yz=5zx then value of x+y+z
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let x + y =5 … … …(1)
& x + z=7 … … …(2)
& y + z=12 … … …(3)
by equation (1), x=5-y , put this value of x in equation (2)
therefore, 5-y+z=7
so, z=7–5+y
so, z=2+y put this value in equation (3)
therefore, y + 2 + y=12
so, y + y=10
hence 2y = 10
so value of y is 5.
By putting its value in equation (1) and (3), we will get value of x=0 and value of z =7.
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