7y^2 - 11/3y - 2/3
find the zeros and verify the relationship between the zeros and coefficients of the polynomials
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Answer:multiply the eq by 3
21y2-11y-2=0
21y2-14y+3y-2=0
7y(3y-2)+1(3y-2)=0
(7y+1)(3y-2)=0
y=-1/7 and y = 2/3
a=7 b=-11/3 c=-2/3
sum of roots is -1/7+2/3=11/21 =-b/a
product of root=-2/21=c/a
Step-by-step explanation:
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