Math, asked by ekam9396, 1 month ago

7y-2=33 solve in error and trail method. ​

Answers

Answered by mamtabirla543
2

Answer:

Answer is in Attachment !!

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Answered by YourHelperAdi
2

trial and error method is a method in we check the equation by taking a number and checking if it is right or not.

hence trial and error method for equation 7y-2= 33 :

1) lets take y as 1 ,

so, 7y-2 = 7(1)-2 = 5

5 is not equal to 33

so, this is not the solution

2) lets take y as 2,

so, 7y-2 = 7(2)-2 = 14-2= 12

12 is not equal to 33

so, 2 is not the solution

3) lets check for 3 ,

so, 7y-2 = 7(3)-2= 21-2 = 19

19 is not equal to 33

so, 3 is not the solution

4) lets check for 4

so, 7y-2 = 7(4)-2= 28-2 = 26

28 is not equal to 33

so, r is not the solution

5) lets cue for 5 ,

so, 7y-2 = 7(5)-2 = 35-2 = 33

33=33

hence, 5is the solution

so,7y-2 =33

y= 5

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