Question

(7y+2)/5=(6y-5)/11 Solve the equation

Answer 1

(7y+2)/5=(6y-5)/11
7y+2=(6y-5)/11 x 5
7y+2=(30y-25)/11
(7y+2)11=30y-25
77y-30y=-25-22
47y=-47
y=-1

Answer 2

(7y+2)/5=(6y-5)/11
⇒$11(7y+2)=5(6y-5)$
⇒$77y+22=30y-25$
⇒$22+25=30y-77y$
⇒$47=-47y$
⇒$y=- \frac{47}{47} =-1$
⇒$Ans:y=-1.$
----------------------------------------------------------------