Question

7y^4-25y^2+12=0 answer this question bro

Answer 1

hay!!

Dear brother -

Given in the question
7y^4-25y²+12

Then,

=> 7y^4-21y²-3y²+12=0

=> 7y²(y²-3)-3(y²-3)=0

=>(7y²-3) (y²-3)=0


I hope it's help you

Answer 2

Hi bro, Harish here.

Here is your answer:

$7y^{4} - 25 y^{2} + 12 = 0$

Now, let us split -25 into -21, -4.

Then

⇒ $7y^{4} - 21y^{2} -3y^{2} + 12 =0$

Now take common then,

⇒  $7y^{2}(y^{2}-3)-3(y^{2}-3) = 0$

⇒  $(7y^{2} -3) (y^{2}-3) =0$
__________________________________________________

Hope my  answer is helpful to you.