7y+4/y+2 = -4/3
solve
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Answered by
1
(7y^2+4+2y)÷y=-4/3
3(7y^2+4+2y)=4y
21y^2+12+6y-4y=0
21y^2+2y+12
now find the value of y using quadratic formula
or splitting middle term
quadratic formula is
[-b± √(b^2-4ac)]÷2a
3(7y^2+4+2y)=4y
21y^2+12+6y-4y=0
21y^2+2y+12
now find the value of y using quadratic formula
or splitting middle term
quadratic formula is
[-b± √(b^2-4ac)]÷2a
Answered by
1
Solve:
→ 3 × (7y+4) = (-4) × (y+2)
→ 21y + 12 = -4y - 8
→ 21 y + 4y = -8-12
→ 25y = -20
→ y = 20/25
→ y = 4/5
Hope it will help u
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