Question

7y+4/y+2=-4/3 what is the answer
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Answer 1

ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT

MARK ME BRAINLIEST ✌✌✌✌

Answer 2

Hello !!

You can solve this question using the following method below, see the same in the practice.

7y + 4/y + 2 = -4/3

7y + 4/y = (-4/3) - (2/1)

7y + 4/y = (-4 - 6)/3

7y + 4/y = (-10/3)

7y = (-10/3) - (4/y)

7y = (-10y - 12)/3y

7y/1 = (-10y - 12)/3y

21y^2 = -10y - 12

21y^2 + 10y + 12 = 0

Well, here you have a quadratic equation and you can use the formula of Bhaskara for you solve it.

Quadratic equation.

21y^2 + 10y + 12 = 0

Coefficients.

A = 21 ; B = 10 and C = 12

Find the value of delta.

Δ = B^2 - 4ac

Δ = 10^2 - 4 × 21 × 12

Δ = 100 - 1008

Δ = -908

Now you calculate the roots.

y = (-b ± √Δ)/2a

y = (-10 ± √(-908))/(2 × 21)

y = (-10 ± 2√227¡)/42

y' = (-10 + 2√227¡)/42

y' = -[(-5 + √227¡)/21]

y'' = (-10 - 2√227¡)/42

y'' = -[(-5 - √227¡)/21]

Therefore, we have that the equation has 2 roots -[(-5 + √227¡)/21] and -[(-5 - √227¡)/21]

I hope I have collaborated !