7y+4/y+2=-4/3 what is the answer
Answers
ANSWER IS IN THE ATTACHMENT PLZZ REFER TO THE ATTACHMENT
MARK ME BRAINLIEST ✌✌✌✌
Hello !!
You can solve this question using the following method below, see the same in the practice.
7y + 4/y + 2 = -4/3
7y + 4/y = (-4/3) - (2/1)
7y + 4/y = (-4 - 6)/3
7y + 4/y = (-10/3)
7y = (-10/3) - (4/y)
7y = (-10y - 12)/3y
7y/1 = (-10y - 12)/3y
21y^2 = -10y - 12
21y^2 + 10y + 12 = 0
Well, here you have a quadratic equation and you can use the formula of Bhaskara for you solve it.
Quadratic equation.
21y^2 + 10y + 12 = 0
Coefficients.
A = 21 ; B = 10 and C = 12
Find the value of delta.
Δ = B^2 - 4ac
Δ = 10^2 - 4 × 21 × 12
Δ = 100 - 1008
Δ = -908
Now you calculate the roots.
y = (-b ± √Δ)/2a
y = (-10 ± √(-908))/(2 × 21)
y = (-10 ± 2√227¡)/42
y' = (-10 + 2√227¡)/42
y' = -[(-5 + √227¡)/21]
y'' = (-10 - 2√227¡)/42
y'' = -[(-5 - √227¡)/21]
Therefore, we have that the equation has 2 roots -[(-5 + √227¡)/21] and -[(-5 - √227¡)/21]
I hope I have collaborated !