Question

7y-5/4y+2 = 8/7 verify also

Answer 1

$\huge\mathcal{\blue {\underline {\overline {\mid {\purple {Answer}}\mid}}}}$

$\frac{7y - 5}{4y + 2} = \frac{8}{7}$

$(7y - 5) \times 7 = (4y + 2) \times 8$

$49y - 35 = 32y + 16$

$49y - 32y = 35 + 16$

$17y = 51$

$y = \frac{51}{17}$

$y = 3$

Verification :-

$\frac{7 \times 3 - 5}{4 \times 3 + 2} = \frac{8}{7}$

$\frac{16}{14} = \frac{8}{7}$

$= \frac{8}{7}$

$\huge \fbox{\orange{Peace✌}}$

Answer 2

5x−4y+8=0⇒a1=5,b1=−4,c1=8

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=75

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.Our system is consistent.

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.Our system is consistent.Answer verified by Toppr

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.Our system is consistent.Answer verified by Toppr1381 Views

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.Our system is consistent.Answer verified by Toppr1381 ViewsUpvote (27)

5x−4y+8=0⇒a1=5,b1=−4,c1=87x+6y−9=0⇒a2=7,b2=6,c2=−9∴a2a1=756−4=3−2c2c1=−98=a2a1=b2b1Therefore we have a unique solution.Our system is consistent.Answer verified by Toppr1381 ViewsUpvote (27)Was this answer helpful?

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