Question

7y²-11/3y-2/3.
find the zeros and also verify the relationship​

Answer 1

Given:-

Find the zeros and also verify the relationship of 7y²-11/3y-2/3.

Solution:-

Let p (y) = 7y²-11/3y-2/3

To find the zeros, we have to take

p (y) = 0

7y²-11/3y-2/3 = 0

Multiply each term with '3' we get

21y²- 11y/3 - 2/3 = 0

21y²- 14y + 3y - 2 = 0

7y (3y - 2) + 1(3y - 2) = 0

(3y - 2) + (7y + 1) = 0

Therefore,

3y - 2 = 0 or 7y + 1 = 0

3y = 2 or 7y = -1

y = 2/3 or y = (-1/7)

Therefore,

Required two zeroes of p(y) are

m = 2/3, n = -1/7

¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤¤

Compare p(y) with ax²+ bx + c, we get

a = 7, b = -11/3, c = 2/3

(1) Sum of the zeroes = -b/a

= - (-11/3)/7

= 11/21----( 1 )

m + n = 2/3 -1/7

= (14 - 3)/21

= 11/21---( 2 )

( 1 ) = ( 2 )

(2) Product of the zeroes = c/a

= (-2/3)/7

= -2/21---( 3 )

mn = (2/3) (-1/7)

= 2/21---( 4 )

( 3 ) = ( 4 )

Answer 2

Answer:

see the attachment for step-by-step solution

Step-by-step explanation:

Mark as brainliest if helpful.