Question

7y²-11/3y-⅔
question of class 10 polynomial​

Answer 1

Answer:

p(y) = 7y² – (11/3)y – 2/3

= 1/3 (21y² – 11y – 2)

= 1/3 [(7 y 1)(3y – 2)]

∴ Zeroes are 2/3, –1/7

Sum of zeroes =(2/3) – ( 1/7)

= -2/21

-b/a = 11/21

∴ sum of zeroes = -b/a

Product of zeroes = (2/3) – ( 1/7)

= – 2/21

c/a = – (2/3) (1/7)

= – 2/21

∴ Product =c/a