Question

(7y²-y-2)-(3y²+2y+8)​

Answer 1

$\huge{\underline{\mathfrak{Answer:-}}}$

$\sf\implies{(7y^2-y-2)-(3y^2+2y+8)}$

$\sf\implies{7y^2-y-2-3y^2-2y-8}$

$\sf\implies{4y^2-3y-10}$

Answer 2

Answer:

7y

2

−y−2)−(3y

2

+2y+8)

\sf\implies{7y^2-y-2-3y^2-2y-8}⟹7y

2

−y−2−3y

2

−2y−8

\sf\implies{4y^2-3y-10}⟹4y

2

−3y−10

hope it helps you

please mark the upper answer as brainliest