Question

7z² - 19z - 6 = ?




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Answer 1

Answer:

I didn't understand!!!!!!!

Answer 2

$7 {z}^{2} - 19z - 6 = 0 \\ 7 {z}^{2} - (21z - 2z) - 6 = 0 \\ 7 {z }^{2} - 21z + 2z - 6 = 0 \\ 7z(z - 3) + 2(z - 3) = 0 \\ (z - 3)(7z + 2) = 0 \\ z - 3 = 0 \: or \: 7z + 2 = 0 \\ z = 3 \: or \: z = - \frac{2}{7} \:$