Question

(8^0 + 7^-1) into 2^3

Answer 1

Answer:

8^0=8^1 then 8

(8-7)8

therefore (1)8 gives 8

I hope this is helpful to you

Answer 2

Step-by-step explanation:

(8^o+7^-1)*1

(1+1/7)*1. ( because a^0=1 and b^-1=1/b)

(7+1/7)*1

8/7*1=8/7