Chemistry, asked by satrox2844, 11 months ago

8.0575 × 10⁻² kg of Glauber’s salt is dissolved in water to obtain 1 dm³ of a solution of density 1077.2 kg m⁻³.

Answers

Answered by daredevil9
2

Answer:

In 1 dm3 solution, weight of Glauber's salt (Na2SO4.10H2O)

= 8.0575 x 10-2 kg 322.3 g of Na2SO4.

10H2O contain 142 g of Na2SO4 8.0575 x 10-2g of Na2SO4.

10H2O

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