8-¹=1/8. ? anybody know it
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Answered by
2
Step-by-step explanation:
It is an identity of exponents that for a real number x,
x^-y = (1/x)^y
Here, x = 8 and y = 1
So, 8^-1 = (1/8)^1 = 1/8
Answered by
5
Answer:
yes your answer is right
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