(8
1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6.
Find the ratio of areas of these triangles.
Answers
Answer:
A₁ /A₂ = 3/4
Step-by-step explanation:
Given
The base of the triangle T₁ = 9 units
The height of the triangle T₁ = 5 units.
Area of the triangle T₁ = 1/2*(base)*(height) sq.units
= 1/2*9*5
A₁ = 45/2 sq.units _____(1)
Given
The base of the triangle T₂ = 10 units
The height of the triangle T₂ = 6 units
Area of the triangle T₂ = 1/2*(base)*(height) sq.units
= 1/2*10*6
A₂ = 30 sq.units ______(2)
∴A₁ /A₂ = (45/2) / 30
= 45 / (2*30)
= 45/60
∴A₁ /A₂ = 3/4
Therefore, the ratio of areas of these triangles is 3 : 4
Step-by-step explanation
GIVEN
Base 1 = 9 cm
Base 2 = 10 cm
Height 1 = 5 cm
Height 2 = 6 cm
___________________________
Let's take 1st Triangle 1 as ABC and 2nd Triangle as DEF
And
AB = 9 cm
BC = 5 cm
DE = 10 cm
EF = 6 cm
___________________________
ABC / DEF
= AB × BC / DE × EF
= 9 × 5 / 10 × 6
= 45 / 60
= 9 / 12 ( Divide by 5 )
= 3 / 4 ( Divide by 3 )
= 3 : 4