Math, asked by jayp07305, 7 months ago

(8)
1 point
The number zeros of cubic polynomial P(x)=27x' - is/are..
(a) 0
(b) 1
(c) 2
(d) 3
ОА
Ов
Ос
OD​

Answers

Answered by Anonymous
1

your ans is 1 because highest power of polynomial = zeros of polynomial

FollOw = FollOw SurE

Answered by abigail95
3

Answer:

Given P(x)=x

3

−x

To find the zeros of P(x), let P(x)=0

⟹x

3

−x=0

⟹x(x

2

−1)=0

⟹x(x−1)(x+1)=0

⟹x=0 and x−1=0 and x+1=0

⟹x=0,1,−1 are the zeros of P(x)

Thus, the number of zeros of P(x) is 3.

Hence, the answer is 3.

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