Question

이나 8 12 16 20 24 28 32 36 40 44 48 52 56 60 64 68 72 76 80 84 in this number what is 11 first line number and last line number
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Answer 1

Answer:

Your input 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76 appears to be an arithmetic sequence

Find the difference between the members

a2-a1=8-4=4

a3-a2=12-8=4

a4-a3=16-12=4

a5-a4=20-16=4

a6-a5=24-20=4

a7-a6=28-24=4

a8-a7=32-28=4

a9-a8=36-32=4

a10-a9=40-36=4

a11-a10=44-40=4

a12-a11=48-44=4

a13-a12=52-48=4

a14-a13=56-52=4

a15-a14=60-56=4

a16-a15=64-60=4

a17-a16=68-64=4

a18-a17=72-68=4

a19-a18=76-72=4

The difference between every two adjacent members of the series is constant and equal to 4

General Form: a

n

=a

1

+(n-1)d

a

n

=4+(n-1)4

a1=4 (this is the 1st member)

an=76 (this is the last/nth member)

d=4 (this is the difference between consecutive members)

n=19 (this is the number of members)

Sum of finite series members

Step-by-step explanation:

Your input 4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76 appears to be an arithmetic sequence

Find the difference between the members

a2-a1=8-4=4

a3-a2=12-8=4

a4-a3=16-12=4

a5-a4=20-16=4

a6-a5=24-20=4

a7-a6=28-24=4

a8-a7=32-28=4

a9-a8=36-32=4

a10-a9=40-36=4

a11-a10=44-40=4

a12-a11=48-44=4

a13-a12=52-48=4

a14-a13=56-52=4

a15-a14=60-56=4

a16-a15=64-60=4

a17-a16=68-64=4

a18-a17=72-68=4

a19-a18=76-72=4

The difference between every two adjacent members of the series is constant and equal to 4

General Form: a

n

=a

1

+(n-1)d

a

n

=4+(n-1)4

a1=4 (this is the 1st member)

an=76 (this is the last/nth member)

d=4 (this is the difference between consecutive members)

n=19 (this is the number of members)

Sum of finite series members