Question

8. 12 years ago the ratio between the ages of A and B was 3:4, respectively. The present
age of A is 15/4 times of C's present age. If C's present age is 10 years, then what is B's
present age (in years)?
[IBPS Clerk, 2013
(a) 48
(b) 46
(c) 60
(d) 54
(e) 36
​

Answer 1

Step-by-step explanation:

At present,

A's age is 3x+12

B's age is 4x+12

C's age is

$\frac{4(3x + 12}{15} = 10$

Then solve.

12x+48=150

12x=102

x=51/6

Answer 2

Answer:

A's age = 15/4 ×10

=75/2 years

A/Q- 75/2x-12/12 =3/4

=4(75-12)=3(2x-12)

=300-48=6x-36

=252+36=6x

=288=6x

=-x=-288/6

=-x==-48

x=-48/-1

Therefore x=48.

Step-by-step explanation:

I have taken x as the value of b.