Question

-8/15, -3x/4 x^4y^2, 9/16xy^3z and -yz^2​

Answer 1

Step-by-step explanation:

This can be done by

x^2+y^2=16

or (x+y)^2–2xy=16

or (x+y)^2=16+2xy

or (x+y)^2=16+2.9

or (x+y)^2=34

:. (x+y)=(+/-)√34

2.Also other than this formula two more formulas can be applied.

i. since, x^2+y^2=16

or 2(x^2+y^2)=16.2

or (x+y)^2+(x-y)^2=32…..(1)

ii. also, xy=9

or 4xy=9.4

or (x+y)^2-(x-y)^2=36…..(2)

By eliminating (2) from (1) we get,

[{(x+y)^2-(x-y)^2=36} + {(x+y)^2+(x-y)^2=32}]

or 2(x+y)^2=68

or (x+y)^2=34

or (x+y)=(+/-)√34