8.15. A body weighs 63 N on the surface of the earth. What
is the gravitational force on it due to the earth at a height equal
to half the radius of the earth?
Answers
Answered by
1
Answer:
due to change in radius value of value of small g change from 9.8so by this weight also changes
Answered by
1
Answer:
279.72
Explanation:
g at earth =9.8m/s^2
at half radius of earth it become 4.44m/s^2=g'
f=mg'
f=63×4.44m/s^2
f=279.7
if you interested to calculate the of g' then use this formula
g'=g/(1+h/R^2)
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