Question

8 ರ ಮೊದಲ 15ಧನ ಅಪವ ತ್ರ್ಯಗಳ ಮೋತ್ತವೇನು ap​

Answer 1

Given:

8 ರ ಮೊದಲ 15ಧನ ಅಪವ ತ್ರ್ಯಗಳ ಮೋತ್ತವೇನು ap​

Find the sum of the first 15 multiples of 8

To find:

The sum of the first 15 multiples of 8

Solution:

The multiples of 8 are → 8, 16, 24, 32, . . .

Since the multiples of 8 are in A.P., so we have,

The first term, a = 8

The common difference, d = 16 - 8 = 8

The no. of terms, n = 15 . . . (since there are 15 multiples of 8)

We know,

$\boxed{\bold{S _n = \frac{n}{2}[2a + (n-1)d] }}$

Now, by substituting the given values of a, d and n in the above formula, we get

$S_1_5 = \frac{15}{2} [(2\times 8) + (15-1)8]$

$\implies S_1_5 = \frac{15}{2} [16 + (14 \times 8)]$

$\implies S_1_5 = \frac{15}{2} [16 + 112]$

$\implies S_1_5 = \frac{15}{2} \times 128$

$\implies S_1_5 = 15\times 64$

$\implies \bold{S_1_5 = 960}$

Thus, the sum of the first 15 multiples of 8 is → 960.

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Answer 2

Answer:

8 ರ ಮೊದಲ 15ಧನ ಅಪವ ತ್ರ್ಯಗಳ ಮೋತ್ತವೇನು ap