Question

(8) 16a ^3- 128/b^3 factorise​

Answer 1

Step-by-step explanation:

(a^3-b^3)=(a-b)(a^2+ab+b^2)

16a^3-128/b^3=16(a^3-8/b^3)

=16(a^3-(2/b)^3)

=16(a-2/b)(a^2+a(2/b)+b^2)

=16(a-2/b)(a^2+2a/b+b^2)