Math, asked by chandashaw93, 6 months ago

8/2-[1+{5/2-(1/3-1/4)}​

Answers

Answered by Anonymous
2

Answer:

\frac{7}{12}

Step-by-step explanation:

 \frac{8}{2}  -  [1   + \{  \frac{5}{2} - ( \frac{1}{3}  -  \frac{1}{4}   )\} \: ] \\  \\  =  \frac{8}{2}  -  [1   + \{  \frac{5}{2} - (  \frac{(4 \times 1) - (3 \times 1)}{3 \times 4}  )\} \: ] \\  \\  =  \frac{8}{2}  -  [1   + \{  \frac{5}{2} - (  \frac{4 - 3}{12}   )\} \: ] \\  \\  =  \frac{8}{2}  -  [1   + \{  \frac{5}{2} - (  \frac{1}{12}  )\} \: ] \\  \\   =  \frac{8}{2}  -  [1   + \{  \frac{5}{2} -   \frac{1}{12}  \} \: ]  \\  \\  =   \frac{8}{2}  -  [1   + \{ \frac{(6 \times 5) - (1 \times 1)}{12}   \} \: ]  \\  \\  =   \frac{8}{2}  -  [1   + \{   \frac{30 - 1}{12} \} \: ]  \\  \\  =   \frac{8}{2}  -  [1   +  \frac{29}{12}  ]  \\  \\  = \frac{8}{2}  -  [ \frac{(12 \times 1) + (1 \times 29)}{12} ]  \\   \\  =  \frac{8}{2}  -  [ \frac{12 + 29}{12} ] \\  \\  =  \frac{8}{2}  -  \frac{41}{12}  \\  \\  =  \frac{(6 \times 8) - (1 \times 41)}{12}  \\  \\  =  \frac{48 - 41}{12}  \\  \\  =  \frac{7}{12}  \\  \\

HOPE IT HELPS YOU

THANKS !

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