Question

: 8 (2-1) +5(22c +3) – 32 (2+2)​

Answer 1

Answer:

Correct option is

A

22C

Step 1: Current through the wire

We know that,

I=

dt

dq

⇒dq=I dt ....(1)

Step 2: Integrating the equation (1) with proper limits

Time interval: t=0s to t=2s

∫dq=∫

0

2

Idt

I=3t

2

+2t+5

⇒q=∫

0

2

(3t

2

+2t+5)dt=[t

3

+t

2

+5t]

0

2

=(8+4+10)=22C

Hence Option (A) is correct