8*2^2x+4*2^x+1=1+2^x
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I think there is a mistake in the question.
8*2^2^x+4*2^x+1=1+2^x (the actual question)
8*2^2^x+4*2^x=2^x
8*2^2^x+4*2^x-2^x= 0
2^x=a
8a^2+4a-a=0
8a^2+3a-a=0
a(8a+3)=0
a=0 or a=-3/8
Hence, x is not solvable
Hope it helps ;)
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