Question

((-8)^2)^3=(-8)^2x find the value of x

Answer 1

$( { { - 8}^{2}) }^{3} = { - 8}^{2x} \: \: \: \: \\ { ({(a}^{m}) }^{n} = {a}^{m \times n} ) \\ { - 8}^{2 \times 3} = { - 8}^{2x} \\ { - 8}^{6 } = { - 8}^{2x} \\ to \: find \: the \: x \: \\ 6 = 2x \\ \frac{6}{2} = x \\ x = 3$

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