8
2(3x + y) 2(3x - y)
2. Formulate the following problems as a pair of equations, and hence find their solutions:
(i) Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours. Find her
speed of rowing in still water and the speed of the current.
2 women and 5 men
Answers
Answer:
Step-by-step explanation:
Let the speed of rowing in still water be x
and speed of current be y
Speed upstream = x+y
Speed downstream = x-y
so x+y = 20/2 = 10 ------------ (1)
and x-y = 4/2 = 2 ----------------(2)
Solve (1) and (2)
x = 6km/hr
y= 4km/hr
Speed of rowing in still water = 6km/hr
Speed of current = 4km/hr
Given : Ritu can row downstream 20 km in 2 hours, and upstream 4 km in 2 hours.
To find : speed of rowing in still water and the speed of the current.
Solution:
Let say Speed of Rowing in Still water = B km/hr
Speed of Current = S km/hr
Speed Down Stream = B + S km/hr
Speed UpStream = B - S km/hr
Distance = Speed * Time
Ritu can row downstream 20 km in 2 hours
=> 20 = (B + S) * 2
=> B + S = 10
upstream 4 km in 2 hours.
=> 4 = (B - S) * 2
=> B - S = 2
B + S = 10
B - S = 2
Adding both
=> 2B = 12 => B = 6
& S = 4
speed of rowing in still water = 6 km/hr
speed of the current. = 4 km/hr
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